我有一个代码正在使用 aiohttp
监听 WebSocket 上的消息。
看起来像:
async for msg in ws:
await self._ws_msg_handler.handle_message(ws, msg, _services)
其中 ws
是 aiohttp.web.WebSocketResponse()
的实例( 原始代码)
在我的测试中,我模拟了 WebSocketResponse()
及其 __aiter__
方法:
def coro_mock(**kwargs):
return asyncio.coroutine(mock.Mock(**kwargs))
@pytest.mark.asyncio
@mock.patch('aiojsonrpc.request_handler.WebSocketMessageHandler')
async def test_rpc_websocket_handler(
MockWebSocketMessageHandler,
rpc_websocket_handler
):
ws_response = 'aiojsonrpc.request_handler.WebSocketResponse'
with mock.patch(ws_response) as MockWebSocketResponse:
MockRequest = mock.MagicMock()
req = MockRequest()
ws_instance = MockWebSocketResponse.return_value
ws_instance.prepare = coro_mock()
ws_instance.__aiter__ = coro_mock(return_value=iter(range(5)))
ws_instance.__anext__ = coro_mock()
handle_msg_result = 'Message processed'
MockWebSocketMessageHandler.handle_message.side_effect = Exception(
handle_msg_result)
msg_handler = MockWebSocketMessageHandler()
with pytest.raises(Exception) as e:
await request_handler.RpcWebsocketHandler(msg_handler)(req)
assert str(e.value) == handle_msg_result
虽然当我运行 测试 时它失败并显示错误消息:
‘async for’ 需要一个带有
__aiter__
方法的对象,得到 MagicMock
=================================================================================== FAILURES ===================================================================================
__________________________________________________________________________ test_rpc_websocket_handler __________________________________________________________________________
MockWebSocketMessageHandler = <MagicMock name='WebSocketMessageHandler' id='140687969989632'>
rpc_websocket_handler = <aiojsonrpc.request_handler.RpcWebsocketHandler object at 0x7ff47879b0f0>
@pytest.mark.asyncio
@mock.patch('aiojsonrpc.request_handler.WebSocketMessageHandler')
async def test_rpc_websocket_handler(
MockWebSocketMessageHandler,
rpc_websocket_handler
):
ws_response = 'aiojsonrpc.request_handler.WebSocketResponse'
with mock.patch(ws_response) as MockWebSocketResponse:
# MockRequest = mock.create_autospec(aiohttp.web_reqrep.Request)
# req = MockRequest(*[None] * 6)
MockRequest = mock.MagicMock()
req = MockRequest()
ws_instance = MockWebSocketResponse.return_value
ret = mock.Mock()
ws_instance.prepare = coro_mock()
ws_instance.__aiter__ = coro_mock(return_value=iter(range(5)))
ws_instance.__anext__ = coro_mock()
handle_msg_result = 'Message processed'
MockWebSocketMessageHandler.handle_message.side_effect = Exception(
handle_msg_result)
msg_handler = MockWebSocketMessageHandler()
with pytest.raises(Exception) as e:
await request_handler.RpcWebsocketHandler(msg_handler)(req)
> assert str(e.value) == handle_msg_result
E assert "'async for' ...got MagicMock" == 'Message processed'
E - 'async for' requires an object with __aiter__ method, got MagicMock
E + Message processed
tests/test_request_handler.py:252: AssertionError
所以它的行为就像 __aiter__()
从未被嘲笑过。在这种情况下我应该如何完成正确的模拟?
更新:
现在我已经找到了一种使代码可测试的 解决方法,但如果有人告诉我如何处理原始问题中描述的问题,我将不胜感激。
原文由 Eugene Naydenov 发布,翻译遵循 CC BY-SA 4.0 许可协议
您可以使模拟类返回一个实现预期接口的对象:
我不认为有一种方法(还)可以正确地模拟一个对象实现
__aiter__
,它可能是一个 python 错误,因为async for
拒绝MagicMock
,即使hasattr(the_magic_mock, '__aiter__')
是True
。编辑(13/12/2017) :自 0.11 以来,库 asynctest 支持异步迭代器和上下文管理器,asynctest.MagicMock 免费提供此功能。