Spring Rest 应用程序中的“不支持内容类型‘application/json；charset=UTF-8’”

Question

当我在 localhost:8080/api/users 上执行 POST 请求以创建新用户时，出现以下错误：

 {
    "timestamp": "2018-05-28T09:44:55.704+0000",
    "status": 415,
    "error": "Unsupported Media Type",
    "message": "Content type 'application/json;charset=UTF-8' not supported",
    "path": "/api/users/"
}

是请求的主体，选择了 JSON (application/json)。即使我删除角色并将其保持为空，它也会出现相同的错误。

标头的内容类型也是 application/json。

这是我的控制器：

 @PostMapping("/api/users" )
public User createUser(@Valid @RequestBody User user) {
    securityService.autologin(user.getUsername(), user.getPassword());
    return userService.createUser(user);
}

UserService 中的 createUser 函数：

 public User createUser(@Valid @RequestBody User user) {
    user.setPassword(bCryptPasswordEncoder.encode(user.getPassword()));
    user.setRoles(new HashSet<>(roleRepository.findAll()));
    return userRepository.save(user);
}

---

编辑

这是我的用户类：

 @Entity
@Table(name = "user")
@EntityListeners(AuditingEntityListener.class)
@JsonIgnoreProperties(value = {"createdAt", "updatedAt"},
                      allowGetters = true)
public class User implements Serializable{

    private static final long serialVersionUID = 1L;

    public User() {
        super();
        // TODO Auto-generated constructor stub
    }

    @Id
    @Column(name = "user_id")
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private long id;

    @Column(name = "user_name")
    private String name;

    @Column(name = "user_email")
    private String email;

    @Column(name = "user_password")
    @NotBlank
    private String password;

    @Column(name = "user_status")
    private String status;

    @Column(name = "user_tel")
    private String tel;

    @Column(name = "user_confirmation")
    private String confirmation;

    @Column(name = "user_birth_date")
    @Temporal(TemporalType.DATE)
    private Date birth_date;

    @Column(nullable = false, updatable = false)
    @Temporal(TemporalType.TIMESTAMP)
    @CreatedDate
    private Date createdAt;

    @Column(nullable = false)
    @Temporal(TemporalType.TIMESTAMP)
    @LastModifiedDate
    private Date updatedAt;

    @JsonManagedReference
    @ManyToMany
    @JoinTable(name = "user_role", joinColumns = @JoinColumn(name = "user_id"), inverseJoinColumns = @JoinColumn(name = "role_id"))
    private Set<Role> roles;

    @Column(name = "username")
    @NotBlank
    private String username;

    public long getId() {
        return id;
    }

    public void setId(long id) {
        this.id = id;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public String getUsername() {
        return username;
    }

    public void setUsername(String username) {
        this.username = username;
    }

    public String getEmail() {
        return email;
    }

    public void setEmail(String email) {
        this.email = email;
    }

    public String getPassword() {
        return password;
    }

    public void setPassword(String password) {
        this.password = password;
    }

    public String getStatus() {
        return status;
    }

    public void setStatus(String status) {
        this.status = status;
    }

    public String getTel() {
        return tel;
    }

    public void setTel(String tel) {
        this.tel = tel;
    }

    public String getConfirmation() {
        return confirmation;
    }

    public void setConfirmation(String confirmation) {
        this.confirmation = confirmation;
    }

    public Date getBirth_date() {
        return birth_date;
    }

    public void setBirth_date(Date birth_date) {
        this.birth_date = birth_date;
    }

    public Date getCreatedAt() {
        return createdAt;
    }

    public Date getUpdatedAt() {
        return updatedAt;
    }

    public void setUpdatedAt(Date updatedAt) {
        this.updatedAt = updatedAt;
    }

    public Set<Role> getRoles() {
        return roles;
    }

    public void setRoles(Set<Role> roles) {
        this.roles = roles;
    }
}

原文由 Ouissal 发布，翻译遵循 CC BY-SA 4.0 许可协议

Answer 1

我能够通过删除@JsonManagedReference 来解决它。

原文由 Ouissal 发布，翻译遵循 CC BY-SA 4.0 许可协议

Answer 2

在我的例子中有一个 Jackson 失败，记录为警告：

Failed to evaluate Jackson deserialization for type [[simple type, class ***]]: com.fasterxml.jackson.databind.JsonMappingException: Conflicting setter definitions for property [...]

我不小心让二传手超载了，所以杰克逊无法解决这个问题，春天已经抛出了 415。

原文由 Klaudia 发布，翻译遵循 CC BY-SA 4.0 许可协议