我是新来的,但让我们直接回答这个问题:当我为一个类项目计算器编写以下代码时,我遇到了一个“令牌错误”。这是完整的错误消息:
Exception in thread "main" java.lang.Error: Unresolved compilation problem:
Syntax error on token "else", delete this token
at calculatorApplet.main(calculatorApplet.java:42)
我写了这段代码:
import java.util.Scanner;
import javax.swing.JOptionPane;
public class calculatorApplet
{
Scanner sc = new Scanner(System.in);
public static void main(String[] args)
{
JOptionPane.showMessageDialog(null, "Welcome to the Calculator!");
String option = JOptionPane.showInputDialog(null, "Which calculator mode do you want?");
if (option.equals("Addition"))
{
Double add1 = Double.parseDouble(JOptionPane.showInputDialog(null, "Okay type the first number(s) of your addition problem."));
Double add2 = Double.parseDouble(JOptionPane.showInputDialog(null, "Now type the second number(s) of your addition problem."));
Double preAdd = add1+add2;
Double Add = preAdd;
JOptionPane.showMessageDialog(null, "The sum is " + Add + ".");
}
else
{
JOptionPane.showMessageDialog(null, "Huh?");
}
if (option.equals("Subtraction"))
{
Double sub1 = Double.parseDouble(JOptionPane.showInputDialog(null, "Okay type the first number(s) of your subtraction problem."));
Double sub2 = Double.parseDouble(JOptionPane.showInputDialog(null, "Now type the second number(s) of your subtraction problem."));
Double preSub = sub1-sub2;
Double Sub = preSub;
JOptionPane.showMessageDialog(null, "The difference is " + Sub + ".");
}
else
{
JOptionPane.showMessageDialog(null, "Huh?");
}
if (option.equals("Multiplication"));
{
Double mult1 = Double.parseDouble(JOptionPane.showInputDialog(null, "Okay type the first number(s) of your multiplication problem."));
Double mult2 = Double.parseDouble(JOptionPane.showInputDialog(null, "Now type the second number(s) of your multiplication problem."));
Double preMult = mult1*mult2;
Double Mult = preMult;
JOptionPane.showMessageDialog(null, "The product is " + Mult + ".");
}
else //Here is the error.
{
JOptionPane.showMessageDialog(null, "Huh?");
} //Here ends the error.
if (option.equals("Division"))
{
Double div1 = Double.parseDouble(JOptionPane.showInputDialog(null, "Okay type the first number(s) of your division problem."));
Double div2 = Double.parseDouble(JOptionPane.showInputDialog(null, "Now type the second number(s) of your division problem."));
Double preDiv = div1/div2;
Double Div = preDiv;
JOptionPane.showMessageDialog(null, "The quotient is " + Div + ".");
}
else
{
JOptionPane.showMessageDialog(null, "Huh?");
}
//End of if statements.
}
}
那是代码,我评论了令牌错误所在的区域。也许解决方案就在我面前。我希望我的代码成为一个计算器,所以如果你们可以修复我的代码,使其不与数学运算冲突。谢谢,我很感激任何帮助。
原文由 Carlos Lombardii 发布,翻译遵循 CC BY-SA 4.0 许可协议
问题是
if
之后的分号。The grammar is
if
(
condition)
expression-or-block {else
expression-or-block }由于
;
是一个空表达式,这适用于 if 子句并且在 then 子句中没有任何反应 - 在您的情况下语法上没有 else 子句,因为您的 if 语句语句以分号结尾,然后是一个简单的块。然后分词器检测到一个悬空的else
令牌并抱怨。