我有这个 XML 文档,它是 SOAP 请求的主体:
<?xml version="1.0" encoding="UTF-8"?>
<mes:SubmitStructureRequest xmlns:mes="http://www.sdmx.org/resources/sdmxml/schemas/v2_1/message" xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:com="http://www.sdmx.org/resources/sdmxml/schemas/v2_1/common" xmlns:str="http://www.sdmx.org/resources/sdmxml/schemas/v2_1/structure" xmlns:reg="http://www.sdmx.org/resources/sdmxml/schemas/v2_1/registry" xmlns:web="http://www.sdmx.org/resources/sdmxml/schemas/v2_1/webservices">
<mes:Header>
<mes:ID>TEST_DFD</mes:ID>
<mes:Test>true</mes:Test>
<mes:Prepared>2013-10-10</mes:Prepared>
<mes:Sender id="TESTER"/>
<mes:Receiver id="ESTAT"/>
</mes:Header>
<mes:SubmitStructureRequest action="Append">
<str:Structures>
<str:Dataflows>
<str:Dataflow agencyID="ESTAT" id="DFD_TEST_21" version="1.0">
<com:Name xml:lang="en">Production in construction, total, building construction, civil engineering (Monthly)</com:Name>
<str:Structure>
<Ref agencyID="ESTAT" class="DataStructure" id="STS" package="datastructure" version="2.0"/>
</str:Structure>
</str:Dataflow>
</str:Dataflows>
</str:Structures>
</mes:SubmitStructureRequest>
</mes:SubmitStructureRequest>
我正在尝试使用这段 Java 代码解析它(流是前面提到的 xml):
InputStream stream = sourceData.getInputStream();
try {
XMLInputFactory factory = XMLInputFactory.newInstance();
XMLStreamReader parser = factory.createXMLStreamReader(stream);
while (parser.hasNext()) {
int event = parser.next();
if (event == XMLStreamConstants.START_ELEMENT) {
for(int i = 0 ; i < parser.getNamespaceCount(); i ++) {
String ns = parser.getNamespaceURI(i);
if(SdmxConstants.getNamespacesV1().contains(ns)) {
return SDMX_SCHEMA.VERSION_ONE;
}
if(SdmxConstants.getNamespacesV2().contains(ns)) {
return SDMX_SCHEMA.VERSION_TWO;
}
if(SdmxConstants.getNamespacesV2_1().contains(ns)) {
return SDMX_SCHEMA.VERSION_TWO_POINT_ONE;
}
}
throw new SdmxSyntaxException("Can not get Scheme Version from SDMX message. Unable to determine structure type from Namespaces- please ensure this is a valid SDMX document");
}
}
throw new SdmxSyntaxException(ExceptionCode.XML_PARSE_EXCEPTION, "No root node found");
} catch(XMLStreamException e) {
throw new SdmxSyntaxException(ExceptionCode.XML_PARSE_EXCEPTION, e);
} finally {
if(stream != null) {
try {
stream.close();
} catch (IOException e) {
throw new RuntimeException(e);
}
}
}
在 int event = parser.next();
点我得到:
com.ctc.wstx.exc.WstxEOFException:序言中出现意外的 EOF
任何想法为什么会这样?
原文由 Dimitris P. 发布,翻译遵循 CC BY-SA 4.0 许可协议
证据表明您实际上已经尝试解析一个空流。
它说在尝试解析序言时发现了 EOF。您向我们展示的 XML 中的序言没有任何问题,特别是没有合理的理由让解析器遇到 EOF。因此,我推断您向我们展示的 XML 并不是解析器实际看到的内容。