我使用 Spring 4 创建一个简单的应用程序。最近,我将 Spring Security 3 添加到项目中,但总是得到错误代码 302(因此它总是重定向到 主页)。
这是我的 安全配置:
@Configuration
@EnableWebMvcSecurity
@ComponentScan(basePackages = { "com.moon.repository" })
public class SecurityConfig extends WebSecurityConfigurerAdapter {
@Override
protected void configure(AuthenticationManagerBuilder auth) throws Exception {
auth.inMemoryAuthentication().withUser("hello").password("world").roles("USER");
}
@Override
public void configure(WebSecurity web) throws Exception {
web
.ignoring().antMatchers("/resources/**", "/views/**");
}
@Override
protected void configure(HttpSecurity http) throws Exception {
http.authorizeRequests()
.antMatchers("/","/home").permitAll()
.anyRequest().authenticated()
.and()
.formLogin()
.loginPage("/home")
.loginProcessingUrl("/acct/signin")
.and()
.logout()
.permitAll();
}
}
我有一个名为 AccountController 的控制器:
@Controller
@RequestMapping(value = "/acct")
public class AccountController {
private final Logger logger = LoggerFactory.getLogger(AccountController.class);
@RequestMapping(value = "/signin", method = RequestMethod.POST)
public String signin(@RequestParam("username") String username,
@RequestParam("password") String password) {
logger.info("======== [username:{0}][password:{1}] ========", username, password);
if ("error@1.1".equalsIgnoreCase(username)) {
return "error";
} else {
return "demo";
}
}
}
我的WEB-INF结构:
WEB-INF
----views
--------home.jsp
--------demo.jsp
--------error.jsp
流程是这样的:
- 用户访问网站
http://mylocal:8080/moon
=> 它显示 home.jsp - 用户按下登录 按钮,它会弹出一个子窗口,要求输入用户名和密码 => 仍在 home.jsp 中
- 用户按下提交按钮 => 我假设它将转到 /acct/signin 并返回 /demo,但我在 Google Chrome 中看到错误 302,然后它再次转到 /home
有任何想法吗 ?我被困了整整 2 天,现在我几乎绝望了……
非常感谢大家来看我的问题
=================================== 第一次更新============= ======================
更新: home.jsp 中的表单
<form:form role="form" method="POST" action="acct/signin"
class="form-signin">
<div class="row">
<div class="col-lg-5">
<input name="username" size="20" type="email"
class="form-control" placeholder="Email address" required
autofocus>
<input name="password" type="password"
class="form-control" placeholder="Password" required>
<button class="btn btn-lg btn-primary btn-block" type="submit">Sign in</button>
</div>
</div>
</form:form>
===================================第二次更新============= ======================
我试图实现 UserDetailsService(不使用内存中的身份验证)但仍然……同样的问题 - 错误 302
AppUserDetailsServiceImpl.java
@Component
public class AppUserDetailsServiceImpl implements UserDetailsService {
private final Logger logger = LoggerFactory.getLogger(AppUserDetailsServiceImpl.class);
@Override
public UserDetails loadUserByUsername(final String username) throws UsernameNotFoundException {
logger.info("loadUserByUsername username=" + username);
logger.info("======== {} ========",SecurityContextHolder.getContext().getAuthentication());
if (!username.equals("hello")) {
throw new UsernameNotFoundException(username + " not found");
}
// creating dummy user details
return new UserDetails() {
private static final long serialVersionUID = 2059202961588104658L;
@Override
public boolean isEnabled() {
return true;
}
@Override
public boolean isCredentialsNonExpired() {
return true;
}
@Override
public boolean isAccountNonLocked() {
return true;
}
@Override
public boolean isAccountNonExpired() {
return true;
}
@Override
public String getUsername() {
return username;
}
@Override
public String getPassword() {
return "world";
}
@Override
public Collection<? extends GrantedAuthority> getAuthorities() {
List<SimpleGrantedAuthority> auths = new java.util.ArrayList<SimpleGrantedAuthority>();
auths.add(new SimpleGrantedAuthority("USER"));
return auths;
}
};
}
日志显示:
[14/08/19 15:16:32:200][INFO ][com.moon.repository.AppUserDetailsServiceImpl][loadUserByUsername](24) loadUserByUsername username=hello
[14/08/19 15:16:32:200][INFO ][com.moon.repository.AppUserDetailsServiceImpl][loadUserByUsername](25) ======== org.springframework.security.authentication.UsernamePasswordAuthenticationToken@f1e4f742: Principal: com.moon.repository.AppUserDetailsServiceImpl$1@e3dc1b1; Credentials: [PROTECTED]; Authenticated: true; Details: org.springframework.security.web.authentication.WebAuthenticationDetails@12afc: RemoteIpAddress: 127.0.0.1; SessionId: 023BC9A8B997ECBD826DD7C33AF55FC7; Granted Authorities: USER ========
原文由 chialin.lin 发布,翻译遵循 CC BY-SA 4.0 许可协议
我相信 Spring 会将您重定向到
/home
因为您实际上并没有通过登录过程对用户进行身份验证。http://mylocal:8080/moon
返回home.jsp视图/acct/signin
),您恰好在 —b5566d6df976713b32c642f5e6-da3 中有一个与 —AccountController
signin
方法的映射/demo
/demo
路径被保护(.anyRequest().authenticated()
)给任何未经身份验证的用户,由于当前用户确实未经身份验证,Spring Security会自动将请求重定向到登录页面/home
(.loginPage("/home")
)使用 InMemoryUserDetailsManagerConfigurer (请参阅 inMemoryAuthentication javadoc),您只能通过配置的凭据成功登录。如果你想要一个成熟的身份验证系统,你必须为你的 Spring Security 配置提供一个 UserDetailsS ervice 实现(通过 userDetailsService 方法)。
编辑:在与 chialin.lin 的对话之后,似乎缺少的配置是一个 defaultSuccessfulUrl ,让 Spring Security 知道一旦通过身份验证将用户重定向到哪里。