将多个数组拼接成一个数组，不重复

Question

我想将 3 个数组的值推送到一个新数组中而不重复相同的值

var a = ["1", "2", "3"];
var b = ["3", "4", "5"];
var c = ["4", "5", "6"];
var d = [];

function newArray(x, y, z) {
    for(var i = 0; i < d.length; i++) {
        if(d.length == -1) {
            d[i].push(a[i])
        }
    }

    for(var i = 0; i < d.length; i++) {
        if(d.length == -1) {
            d[i].push(y[i])
        }
    }

    for(var i = 0; i < d.length; i++) {
        if(d.length == -1) {
            d[i].push(z[i])
        }
    }
}

newArray(a, b, c);

d = ["1", "2", "3", "4", "5", "6"];

原文由 Raheel Nawab 发布，翻译遵循 CC BY-SA 4.0 许可协议

Answer 1

var a = ["1","2","3"]
  , b = ["3","4","5"]
  , c = ["4","5","6"]
  , d = [];

function newArray(x,y,z) {
  x.concat(y,z).forEach(item =>{
     if (d.indexOf(item) == -1)
       d.push(item);
  });
  return d;
}

console.log(newArray(a,b,c));

原文由 BrTkCa 发布，翻译遵循 CC BY-SA 3.0 许可协议

Answer 2

如果您的目标是删除重复项，则可以使用一组，

 var arr = [1, 2, 3, 4, 5, 5, 6, 6, 6, 7]
var mySet = new Set(arr)
var filteredArray = Array.from(mySet)
console.log(filteredArray.sort()) // [1,2,3,4,5,6,7]

原文由 chatton 发布，翻译遵循 CC BY-SA 4.0 许可协议