在 React JS 中按日期排序数组

Question

我有一个对象数组，如下所示：

 let cars = [
    {"id":20,"mileage":41300,"make":"Golf", initialRegistration:"09/02/2010"},
    {"id":21,"mileage":51300,"make":"Passat", initialRegistration:"06/04/2012"},
    {"id":22,"mileage":61300,"make":"Audi", initialRegistration:"02/01/2018"},
    {"id":23,"mileage":20300,"make":"Touran", initialRegistration:"17/09/2013"},
    {"id":24,"mileage":10300,"make":"Polo", initialRegistration:"26/07/2014"}
];

我想按 initialRegistration 排序。

我尝试按如下方式进行：

 let sortedCars = cars.sort((a, b) => Date.parse(a.initialRegistration) - Date.parse(b.initialRegistration));

let sortedCars1 = cars.sort((a, b) => new Date(a.initialRegistration) - new Date(b.initialRegistration));

let sortedCars2 = cars.sort((a, b) => new Date(a.initialRegistration).getTime() - new Date(b.initialRegistration).getTime());

但是这些尝试都没有奏效。我得到的结果是：

 Golf - 09/02/2010
Passat - 06/04/2012
Audi - 02/01/2018
Touran - 17/09/2013
Polo - 26/07/2014

这是小提琴。

原文由 Boky 发布，翻译遵循 CC BY-SA 4.0 许可协议

Answer 1

使用 Date 构造函数并执行类似的操作。

 let sortedCars1 = cars.sort((a, b) => new Date(...a.initialRegistration.split('/').reverse()) - new Date(...b.initialRegistration.split('/').reverse()));

 let cars = [{
  "id": 20,
  "mileage": 41300,
  "make": "Golf",
  initialRegistration: "09/02/2010"
}, {
  "id": 21,
  "mileage": 51300,
  "make": "Passat",
  initialRegistration: "06/04/2012"
}, {
  "id": 22,
  "mileage": 61300,
  "make": "Audi",
  initialRegistration: "02/01/2018"
}, {
  "id": 23,
  "mileage": 20300,
  "make": "Touran",
  initialRegistration: "17/09/2013"
}, {
  "id": 24,
  "mileage": 10300,
  "make": "Polo",
  initialRegistration: "26/07/2014"
}];

let sortedCars1 = cars.sort((a, b) => new Date(...a.initialRegistration.split('/').reverse()) - new Date(...b.initialRegistration.split('/').reverse()));

console.log(sortedCars1);

---

或者在反转日期字符串后使用 String#localeCompare 进行字符串比较。

 let sortedCars1 = cars.sort((a, b) =>
  a.initialRegistration.split('/').reverse().join().localeCompare(b.initialRegistration.split('/').reverse().join()));

 let cars = [{
  "id": 20,
  "mileage": 41300,
  "make": "Golf",
  initialRegistration: "09/02/2010"
}, {
  "id": 21,
  "mileage": 51300,
  "make": "Passat",
  initialRegistration: "06/04/2012"
}, {
  "id": 22,
  "mileage": 61300,
  "make": "Audi",
  initialRegistration: "02/01/2018"
}, {
  "id": 23,
  "mileage": 20300,
  "make": "Touran",
  initialRegistration: "17/09/2013"
}, {
  "id": 24,
  "mileage": 10300,
  "make": "Polo",
  initialRegistration: "26/07/2014"
}];

let sortedCars1 = cars.sort((a, b) =>
  a.initialRegistration.split('/').reverse().join().localeCompare(b.initialRegistration.split('/').reverse().join()));

console.log(sortedCars1);

原文由 Pranav C Balan 发布，翻译遵循 CC BY-SA 3.0 许可协议

Answer 2

实际上日期解析没有正确发生 new Date(“09/02/2010”) 将不起作用，并将假定日期为 2010 年 9 月 2 日，因此需要将其作为 “2010-02-09” yyyy-mm-dd 传递

  let sortedCars = cars.sort((a, b) => Date.parse(new Date(a.initialRegistration.split("/").reverse().join("-"))) - Date.parse(new Date(b.initialRegistration.split("/").reverse().join("-"))));

看到这个 http://jsfiddle.net/jwm6k66c/1590/

原文由 Vinod Louis 发布，翻译遵循 CC BY-SA 3.0 许可协议