为什么用python求两数间素数和会输出一堆等于号？

Question

def num(n):
 for i in range(2,n):
    if n %i == 0:
        return 0
    break
 else:
    return n

a = int(input())
b = int(input())
s = 0
for n in range(a,b+1):
    s += num(n)
    if n == 1:       
        print("he%d"%s-1)
    else:
        print("he%d"%s)

Answer 1

因为函数每次调用只能有一个返回值，换成列表再计算吧！

def num(n):
    return [n if n%i!=0 else (n-n) for i in range(2,n)]#条件if else生成列表推导式
a = int(input())
b = int(input())
s = 0
for n in range(a,b+1):
    for t in num(n):#此处原来返回none,none与int不能运算
        s += t#拆开返回的列表推导式进行运算
    if n == 1:
        print("he%d"%(s-1))#不同数据类型不能运算，先运算再合并字符串
    else:
        print("he%d"%s)

Answer 2

def num(n):
 for i in range(2,n):
    if n %i == 0:
        return 0
    else:
        return n

# a = int(input())
# b = int(input())
a = 10
b = 50
s = 0
result = []
for n in range(a,b+1):
    if(num(n) != 0):
        result.append( num(n))
        s += num(n)

if __name__ == '__main__':
    print(result)
    print(s)