js优化代码？

Question

如图，searchData是一个对象，想在搜索的时候去掉其中满足条件的几个属性，有什么更好的写法吗

Answer 1

写了这么多年代码，你现在这种写法是最容易阅读的。越优雅的代码，越难看懂，并不是代码越少越好。代码压缩交给工具做就好了，自己写保证逻辑清晰易懂就i行

Answer 2

const { interviewStatus, status, ...rest } = this.searchData;
if (status !== "1") {
    rest.status = status;
}
// 使用rest
api.get(rest)

Answer 3

async search(){
  Reflect.deleteProperty(this.searchData.interviewStatus)
  Reflect.deleteProperty(this.searchData,this.form.status==='1'?'status':'isChooseAllDelivery')
}

Answer 4

async search(){
    delete this.searchData.interviewStatus;
    var str = this.from.status === "1"? status :searchChooseAllDeliverty;
    delete this.searchData[str];
}

Answer 5

let deleteKeys = ['interviewStatus']

deleteKeys.push(this.form.status === '1' ? 'status' : 'isChooseAllDelivery')

deleteKeys.forEach(key => {
  delete this.searchData[key]
})