字典更新序列元素 #0 的长度为 3; 2 是必需的

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我想通过其他对象向对象添加行 account.bank.statement.line 但我收到以下错误:

“字典更新序列元素 #0 的长度为 3;需要 2”

这是我的代码:

 def action_account_line_create(self, cr, uid, ids):
    res = False
    cash_id = self.pool.get('account.bank.statement.line')
    for exp in self.browse(cr, uid, ids):
        company_id = exp.company_id.id
        #statement_id = exp.statement_id.id
        lines = []
        for l in exp.line_ids:
            lines.append((0, 0, {
                'name': l.name,
                'date': l.date,
                'amount': l.amount,
                'type': l.type,
                'statement_id': exp.statement_id.id,
                'account_id': l.account_id.id,
                'account_analytic_id': l.analytic_account_id.id,
                'ref': l.ref,
                'note': l.note,
                'company_id': l.company_id.id
            }))

        inv_id = cash_id.create(cr, uid, lines,context=None)
        res = inv_id
    return res

我改变了它,但后来我遇到了这个错误:

   File "C:\Program Files (x86)\OpenERP 6.1-20121029-003136\Server\server\.\openerp\workflow\wkf_expr.py", line 68, in execute
  File "C:\Program Files (x86)\OpenERP 6.1-20121029-003136\Server\server\.\openerp\workflow\wkf_expr.py", line 58, in _eval_expr
  File "C:\Program Files (x86)\OpenERP 6.1-20121029-003136\Server\server\.\openerp\tools\safe_eval.py", line 241, in safe_eval
  File "C:\Program Files (x86)\OpenERP 6.1-20121029-003136\Server\server\.\openerp\tools\safe_eval.py", line 108, in test_expr
  File "<string>", line 0
   ^
SyntaxError: unexpected EOF while parsing

代码:

 def action_account_line_create(self, cr, uid, ids, context=None):
    res = False
    cash_id = self.pool.get('account.bank.statement.line')
    for exp in self.browse(cr, uid, ids):
        company_id = exp.company_id.id
        lines = []
        for l in exp.line_ids:
            res = cash_id.create ( cr, uid, {
                'name': l.name,
                'date': l.date,
                'amount': l.amount,
                'type': l.type,
                'statement_id': exp.statement_id.id,
                'account_id': l.account_id.id,
                'account_analytic_id': l.analytic_account_id.id,
                'ref': l.ref,
                'note': l.note,
                'company_id': l.company_id.id
            }, context=None)
    return res

原文由 rindra 发布,翻译遵循 CC BY-SA 4.0 许可协议

阅读 580
2 个回答

出现此错误是因为您尝试使用错误的序列( listtuple )结构更新 dict 对象。

cash_id.create(cr, uid, lines,context=None) 尝试将 lines 转换成字典对象:

 (0, 0, {
    'name': l.name,
    'date': l.date,
    'amount': l.amount,
    'type': l.type,
    'statement_id': exp.statement_id.id,
    'account_id': l.account_id.id,
    'account_analytic_id': l.analytic_account_id.id,
    'ref': l.ref,
    'note': l.note,
    'company_id': l.company_id.id
})

从此元组中删除第二个零以将其正确转换为 dict 对象。

要自己测试它,请在 python shell 中尝试:

 >>> l=[(0,0,{'h':88})]
>>> a={}
>>> a.update(l)

Traceback (most recent call last):
  File "<pyshell#11>", line 1, in <module>
    a.update(l)
ValueError: dictionary update sequence element #0 has length 3; 2 is required

>>> l=[(0,{'h':88})]
>>> a.update(l)

原文由 MBarsi 发布,翻译遵循 CC BY-SA 4.0 许可协议

当我用错误的语法更新字典时出现此错误:

试试这些:

 lineItem.values.update({attribute,value})

代替

lineItem.values.update({attribute:value})

原文由 Ian Michel 发布,翻译遵循 CC BY-SA 4.0 许可协议

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