颠倒图例的顺序

新手上路,请多包涵

我使用以下代码绘制条形图,需要以相反的顺序显示图例。我该怎么做?

 colorsArr = plt.cm.BuPu(np.linspace(0, 0.5, len(C2)))
p = numpy.empty(len(C2), dtype=object)
plt.figure(figsize=(11, 11))

prevBar = 0
for index in range(len(C2)):
    plt.bar(ind, C2[index], width, bottom=prevBar, color=colorsArr[index],
            label=C0[index])
    prevBar = prevBar + C2[index]

# Positions of the x-axis ticks (center of the bars as bar labels)
tick_pos = [i + (width/2) for i in ind]

plt.ylabel('Home Category')
plt.title('Affinity - Retail Details(Home category)')

# Set the x ticks with names
plt.xticks(tick_pos, C1)
plt.yticks(np.arange(0, 70000, 3000))
plt.legend(title="Line", loc='upper left')

# Set a buffer around the edge
plt.xlim(-width*2, width*2)
plt.show()

原文由 YAKOVM 发布,翻译遵循 CC BY-SA 4.0 许可协议

阅读 795
2 个回答

你可以打电话

handles, labels = ax.get_legend_handles_labels()
ax.legend(handles[::-1], labels[::-1], title='Line', loc='upper left')


 import numpy as np
import matplotlib.pyplot as plt
np.random.seed(2016)

C0 = list('ABCDEF')
C2 = np.random.randint(20000, size=(len(C0), 3))
width = 1.0
C1 = ['foo', 'bar', 'baz']
ind = np.linspace(-width, width, len(C1))

colorsArr = plt.cm.BuPu(np.linspace(0, 0.5, len(C2)))
fig = plt.figure(figsize=(11,11))
ax = fig.add_subplot(1, 1, 1)

prevBar = 0
for height, color, label in zip(C2, colorsArr, C0):
    h = ax.bar(ind, height, width, bottom=prevBar, color=color, label=label)
    prevBar = prevBar + height

plt.ylabel('Home Category')
plt.title('Affinity - Retail Details(Home category)')

# positions of the x-axis ticks (center of the bars as bar labels)
tick_pos = [i+(width/2.0) for i in ind]
# set the x ticks with names
plt.xticks(tick_pos, C1)
plt.yticks(np.arange(0,70000,3000))

handles, labels = ax.get_legend_handles_labels()
ax.legend(handles[::-1], labels[::-1], title='Line', loc='upper left')

plt.show()

在此处输入图像描述

原文由 unutbu 发布,翻译遵循 CC BY-SA 3.0 许可协议

或者你可以使用更简单的

handles, labels = ax.get_legend_handles_labels()
ax.legend(reversed(handles), reversed(labels), title='Line', loc='upper left')

原文由 Vaiaro 发布,翻译遵循 CC BY-SA 4.0 许可协议

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