如何在 python discord bot 中获取用户输入？

Question

我有一个 python discord bot，我需要它在命令后获取用户输入，我该怎么做？我是 python 的新手，正在制作不和谐的机器人。这是我的代码：

 import discord, datetime, time
from discord.ext import commands
from datetime import date, datetime

prefix = "!!"
client = commands.Bot(command_prefix=prefix, case_insensitive=True)

times_used = 0

@client.event
async def on_ready():
  print(f"I am ready to go - {client.user.name}")
  await client.change_presence(activity=discord.Activity(type=discord.ActivityType.watching, name=f"{client.command_prefix}python_help. This bot is made by drakeerv."))

@client.command(name="ping")
async def _ping(ctx):
  global times_used
  await ctx.send(f"Ping: {client.latency}")
  times_used = times_used + 1

@client.command(name="time")
async def _time(ctx):
  global times_used
  from datetime import date, datetime

  now = datetime.now()

  if (now.strftime("%H") <= "12"):
    am_pm = "AM"
  else:
    am_pm = "PM"

  datetime = now.strftime("%m/%d/%Y, %I:%M")

  await ctx.send("Current Time:" + ' '  + datetime + ' ' + am_pm)
  times_used = times_used + 1

@client.command(name="times_used")
async def _used(ctx):
  global times_used
  await ctx.send(f"Times used since last reboot:" + ' ' + str(times_used))
  times_used = times_used + 1

@client.command(name="command") #THIS LINE
async def _command(ctx):
  global times_used
  await ctx.send(f"y or n")
  times_used = times_used + 1

@client.command(name="python_help")
async def _python_help(ctx):
  global times_used
  msg = '\r\n'.join(["!!help: returns all of the commands and what they do.",
                     "!!time: returns the current time.",
                     "!!ping: returns the ping to the server."])
  await ctx.send(msg)
  times_used = times_used + 1

client.run("token")

我正在使用 python 版本 3.8.3。我已经看过其他帖子，但他们没有回答我的问题或给我错误。任何帮助将不胜感激！

原文由 drakeerv 发布，翻译遵循 CC BY-SA 4.0 许可协议

Answer 1

你会想要使用 Client.wait_for() ：

 @client.command(name="command")
async def _command(ctx):
    global times_used
    await ctx.send(f"y or n")

    # This will make sure that the response will only be registered if the following
    # conditions are met:
    def check(msg):
        return msg.author == ctx.author and msg.channel == ctx.channel and \
        msg.content.lower() in ["y", "n"]

    msg = await client.wait_for("message", check=check)
    if msg.content.lower() == "y":
        await ctx.send("You said yes!")
    else:
        await ctx.send("You said no!")

    times_used = times_used + 1

超时：

 import asyncio # To get the exception

@client.command(...)
async def _command(ctx):
    # code
    try:
        msg = await client.wait_for("message", check=check, timeout=30) # 30 seconds to reply
    except asyncio.TimeoutError:
        await ctx.send("Sorry, you didn't reply in time!")

---

参考：

• Client.wait_for() - 这里有更多例子
• Message.author
• Message.channel
• Message.content
• asyncio.TimeoutError

原文由 Diggy. 发布，翻译遵循 CC BY-SA 4.0 许可协议

Answer 2

有了这个你可以做这样的事情

@client.command()
async def command(ctx):
    computer = random.randint(1, 10)
    await ctx.send('Guess my number')

    def check(msg):
        return msg.author == ctx.author and msg.channel == ctx.channel and int(msg.content) in [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

    msg = await client.wait_for("message", check=check)

    if int(msg.content) == computer:
        await ctx.send("Correct")
    else:
        await ctx.send(f"Nope it was {computer}")

原文由 Flat Dat 发布，翻译遵循 CC BY-SA 4.0 许可协议