Python 中的计算器循环

Question

需要向我的计算器添加一个循环，方法是让用户可以选择重新启动计算器，方法是将代码放在一个 while 循环中，条件是用户的输入应该是“y”或“Y”。

 def add(x, y):
   return x + y

def subtract(x, y):
   return x - y

def multiply(x, y):
   return x * y

def divide(x, y):
   return x / y

print("Select operation.")
print("1.Add")
print("2.Subtract")
print("3.Multiply")
print("4.Divide")

choice = input("Enter choice(1/2/3/4):")

num1 = int(input("Enter first number: "))
num2 = int(input("Enter second number: "))

if choice == '1':
   print(num1,"+",num2,"=", add(num1,num2))

elif choice == '2':
   print(num1,"-",num2,"=", subtract(num1,num2))

elif choice == '3':
   print(num1,"*",num2,"=", multiply(num1,num2))

elif choice == '4':
   print(num1,"/",num2,"=", divide(num1,num2))
else:
   print("Invalid input")

原文由 rko 发布，翻译遵循 CC BY-SA 4.0 许可协议

Answer 1

只需在 Alex 的帖子中添加一些内容

cont = "y"
while cont.lower() == "y":
    print("Select operation\n1.Add\n2.Subtract\n3.Multiply\n4.Divide")

    choice = input("Enter choice(1/2/3/4):")

    num1 = int(input("Enter first number: "))
    num2 = int(input("Enter second number: "))

    if choice == '1':
       print(num1,"+",num2,"=", (num1 + num2))

    elif choice == '2':
       print(num1,"-",num2,"=", (num1 - num2))

    elif choice == '3':
       print(num1,"*",num2,"=", (num1 * num2))

    elif choice == '4':
       print(num1,"/",num2,"=", (num1 / num2))
    else:
       print("Invalid input")
    cont = input("Continue?y/n:")
    if cont == "n":
        break

原文由 MarcoPolo 发布，翻译遵循 CC BY-SA 3.0 许可协议