TypeError：\* 不支持的操作数类型：'float' 和 'NoneType'

Question

当我尝试在另一个函数中使用函数时

错误

TypeError：* 不支持的操作数类型：’float’ 和 ‘NoneType’

 # Function to calculate 2D circularity ratio
def defineCircularRatio(perim2D, area2D):

    circularity_ratio = (4*math.pi*area2D)/(perim2D**2)

    return circularity_ratio

    print "The 2D circul_ratio is:", circularity_ratio

周长和面积 - 由其他函数计算。

原文由 asdqwery 发布，翻译遵循 CC BY-SA 4.0 许可协议

Answer 1

这是给出错误的行：

 circularity_ratio = (4*math.pi*area2D)/(perim2D**2)

Now since it has float before NoneType in the error and math.pi is a float itself, this means that perim2D was never defined or is等于零，因此 NoneType 。 perim2D 声明为整数或浮点数以防止错误。例如：

 variable = 2
other_variable = 3

def defineCircularRatio(perim2D, area2D):

    circularity_ratio = (4*math.pi*area2D)/(perim2D**2)

    return circularity_ratio

    print "The 2D circul_ratio is:", circularity_ratio

defineCircularRatio(variable, other_variable)

The above code variable as perim2D , which solves the problem as perim2D is no longer equal to None but to 2. other_variable 曾经被分配给 area2D 。

原文由 Anthony Pham 发布，翻译遵循 CC BY-SA 3.0 许可协议