文件夹中的文件列表/DRIVE API PyDRIVE

Question

我无法更改文件夹和查看里面的内容。

 drive = GoogleDrive(gauth)
file_list = drive.ListFile({'q': "'root' in parents and trashed=false"}).GetList()
for file1 in file_list:
print("File %s\n\n",(file1))

我使用了以下代码：

 file_list = drive.ListFile({'q': "'/test1' in parents and trashed=false"}).GetList()

但它不起作用。有我使用的函数的文档： https ://developers.google.com/drive/v3/reference/files/list

原文由 simone989 发布，翻译遵循 CC BY-SA 4.0 许可协议

Answer 1

您必须插入文件夹 ID 而不是其路径。您可以通过不同的方式获取 ID：

1. 使用 PyDrive：如果列出根目录中的所有文件夹，则可以列出所有文件夹名称及其各自的 ID。
2. 使用 Web 界面：导航到要从中获取 ID 的文件夹。查看 URL，它具有以下格式： drive.google.com/drive/u/0/folders/<folder ID>

现在将文件夹 ID 插入到请求中。

 file_list = drive.ListFile({'q': "'<folder ID>' in parents and trashed=false"}).GetList()

仅供参考：Google Drive 是一个基于标签（也称为语义）的文件系统，例如，它允许一个文件同时位于多个位置（只需将文件夹的 ID 添加到文件的 parents 财产）。

原文由 Robin Nabel 发布，翻译遵循 CC BY-SA 3.0 许可协议

Answer 2

以下是使用 pydrive 打印 Google 驱动器文件结构的两个完整工作示例 - 按照代码中的注释进行操作。

---

示例 1 - pydrive 的基本用法和打印顶级文件夹

from pydrive.auth import GoogleAuth
from pydrive.drive import GoogleDrive

gauth = GoogleAuth()
gauth.LocalWebserverAuth()
drive = GoogleDrive(gauth)

# 1) Choose your starting point by inserting file name
folder_title = "your-starting-point-folder"
folder_id = ''

# 2) Retrieve the folder id - start searching from root
file_list = drive.ListFile({'q': "'root' in parents and trashed=false"}).GetList()
for file in file_list:
    if(file['title'] == folder_title):
        folder_id = file['id']
        break

# 3) Build string dynamically (need to use escape characters to support single quote syntax)
str = "\'" + folder_id + "\'" + " in parents and trashed=false"

# 4) Starting iterating over files
file_list = drive.ListFile({'q': str}).GetList()
for file in file_list:
    print('title: %s, id: %s' % (file['title'], file['id']))

---

示例 2 - 递归打印所有文件结构

我使用了一个名为 treelib 的树可视化库。

 from treelib import Node, Tree

from pydrive.auth import GoogleAuth
from pydrive.drive import GoogleDrive

gauth = GoogleAuth()
gauth.LocalWebserverAuth()
drive = GoogleDrive(gauth)

### Some basic helper functions ###
def get_children(root_folder_id):
    str = "\'" + root_folder_id + "\'" + " in parents and trashed=false"
    file_list = drive.ListFile({'q': str}).GetList()
    return file_list

def get_folder_id(root_folder_id, root_folder_title):
    file_list = get_children(root_folder_id)
    for file in file_list:
        if(file['title'] == root_folder_title):
            return file['id']

def add_children_to_tree(tree, file_list, parent_id):
    for file in file_list:
        tree.create_node(file['title'], file['id'], parent=parent_id)
        # For debugging
        # print('parent: %s, title: %s, id: %s' % (parent_id, file['title'], file['id']))

### Go down the tree until you reach a leaf ###
def populate_tree_recursively(tree,parent_id):
    children = get_children(parent_id)
    add_children_to_tree(tree, children, parent_id)
    if(len(children) > 0):
        for child in children:
            populate_tree_recursively(tree, child['id'])

### Create the tree and the top level node ###
def main():
    root_folder_title = "my-top-level-root-folder-name"
    root_folder_id = get_folder_id("root", root_folder_title)

    tree = Tree()
    tree.create_node(root_folder_title, root_folder_id)
    populate_tree_recursively(tree, root_folder_id)
    tree.show()

if __name__ == "__main__":
    main()

原文由 RtmY 发布，翻译遵循 CC BY-SA 4.0 许可协议