组播ip地址校验问题？

Question

如题，我想使用JavaScript校验组播ip地址，地址范围是224.0.1.0 - 239.255.255.255，请问正则表达式要怎么编写？

Answer 1

export function multicastIp (ip: string) {
  const pattern = /^(224\.0(\.([1-9]|[1-9]\d|1\d{2}|2[0-4]\d|25[0-5]))(\.(\d|[1-9]\d|1\d{2}|2[0-4]\d|25[0-5])))$|^(224)(\.([1-9]|[1-9]\d|1\d{2}|2[0-4]\d|25[0-5]))(\.(\d|[1-9]\d|1\d{2}|2[0-4]\d|25[0-5])){2}$|^(22[5-9]|23[0-9])(\.(\d|[1-9]\d|1\d{2}|2[0-4]\d|25[0-5])){3}$/
  return pattern.test(ip)
}

分别匹配224.0.1-255.x 224.1-255.x.x 225-239.x.x，其中x的取值为0-255

Answer 2

function isValidMulticastIP(ip) {
  const ipPattern = /^(\d{1,3})\.(\d{1,3})\.(\d{1,3})\.(\d{1,3})$/;
  const match = ip.match(ipPattern);
  if (!match) {
    return false;
  }

  const parts = match.slice(1).map(Number);

  if (parts.some(part => part < 0 || part > 255)) {
    return false;
  }

  if (parts[0] === 224 && parts[1] === 0 && parts[2] === 0 && parts[3] === 0) {
    return false;
  }

  return parts[0] >= 224 && parts[0] <= 239;
}

Answer 3

function checkIp(ip) {
    const start = '224.0.1.0'
    const end = '239.255.255.255'
    const ipSum = ip => +ip.split('.').map(n => n.padStart(3,'0')).join('')
    const n = ipSum(ip)
    return n >= ipSum(start) && n <= ipSum(end)
}

对于传入的ip假设其是正确的，如果ip有可能格式不对（比如超过255，或者少传之类的）自己再加一层校验，这里只提供比较的逻辑，对ip的数值部分填满三个字符，然后拼接起来成一个数值来进行比较

Answer 4

const multicastIPRegex = /^(22[4-9]|23[0-9])\.([01]?[0-9]{1,2}|2[0-4][0-9]|25[0-5])\.([01]?[0-9]{1,2}|2[0-4][0-9]|25[0-5])\.([01]?[0-9]{1,2}|2[0-4][0-9]|25[0-5])$/;

// 示例用法
const ipAddress = '225.10.20.30';
if (multicastIPRegex.test(ipAddress)) {
  console.log('有效的组播IP地址');
} else {
  console.log('无效的组播IP地址');
}

Answer 5

补充另外一条正则
^2((3\d|2[5-9])(\.(1\d{0,2}|2([0-4]\d|5[0-5])|[2-9]\d?|0)){3}|24\.((1\d{0,2}|2([0-4]\d|5[0-5])|[2-9]\d?)(\.(1\d{0,2}|2([0-4]\d|5[0-5])|[2-9]\d?|0)){2}|0\.(1\d{0,2}|2([0-4]\d|5[0-5])|[2-9]\d?)(\.(1\d{0,2}|2([0-4]\d|5[0-5])|[2-9]\d?|0))))$
PS,其中的数值区间我有个网页工具可以生成：https://www.regex.top