请问大家 两个数组对象的组合方法，谢谢大家？

Question

 let arr1 = [
                  {
                    cart_goods:[{
                      goods_id:1,
                      is_purchase:1,
                      is_checked:false
                    }]
                  },
                  {
                    cart_goods:[{
                      goods_id:2,
                      is_purchase:1,
                      is_checked:false
                    }]
                  }
                ]
let arr2 = [
  {
    cart_goods:[{
      goods_id:1,
      is_purchase:0,
      is_checked:true
    }]
  },
  {
    cart_goods:[{
      goods_id:2,
      is_purchase:0,
      is_checked:true
    }]
  }
]

我想把arr2中的is_checked 属性值 复制给 arr1中的is_checked 想要的结果是：

 let arr1 = [
                  {
                    cart_goods:[{
                      goods_id:1,
                      is_purchase:1,
                      is_checked:true
                    }]
                  },
                  {
                    cart_goods:[{
                      goods_id:2,
                      is_purchase:1,
                      is_checked:true
                    }]
                  }
                ]

以为是个双重循环，有点不知道怎么写

Answer 1

arr1.forEach(({ cart_goods }, i) => {
    cart_goods[0].is_checked = arr2[i].cart_goods[0].is_checked;
});
console.log(arr1);

Answer 2

因为是想把arr2的is_checked值赋给arr1，所以建议拿arr2来做循环

arr2.forEach((arr2_item, index) => {
    const value = arr2_item.cart_goods[0].is_checked;
    const arr1_item = arr1[index];
    if (arr1_item) {
        arr1_item.cart_goods[0].is_checked = value
    } else {
        return;
    }
});

Answer 3

如果你两个索引一致那就双重循环，通过索引去找到对应元素
arr2.forEach((v,i) => v.cart_goods.forEach((e,j) => arr1[i].cart_goods[j].is_checked = e.is_checked))

Answer 4

let newArr = arr1.map((item, index) => {
  let newItem = Object.assign({}, item);
  newItem.cart_goods = item.cart_goods.map((cartItem, cartIndex) => {
    return {
      ...cartItem,
      is_checked: arr2[index].cart_goods[cartIndex].is_checked
    };
  });
  return newItem;
});

console.log(newArr);

Answer 5

let result = arr1.reduce((acc, item, index) => {
  let newItem = {...item};
  newItem.cart_goods = newItem.cart_goods.map((cartItem, cartIndex) => {
    return {
      ...cartItem,
      is_checked: arr2[index].cart_goods[cartIndex].is_checked
    };
  });
  acc.push(newItem);
  return acc;
}, []);

console.log(result);