Elasticsearch 中的 terms 聚合，如何得到所有 buckets 的数量？

Question

GET /mini_program_visit_log_230731/_search
{
    "size": 0,
    "query": {
        "bool": {
            "must": [
                { "match": { "page_path.keyword": "page/pages/webviewPage/webviewPage/bunny_jump" }},
                { "match": { "brand_id": 2617 }},
                {
                 "range": {
                   "create_time": {
                     "gte": 1690772400000,
                     "lte": 1690774200000
                   }
                 }
                }
            ]
        }
    },
    "aggs": {
      "unique_values": {
        "terms": {
          "field": "member_id"
        }
      }
    }
}

查询结果集：

{
  "hits" : {
    "total" : {
      "value" : 230,
      "relation" : "eq"
    },
    "max_score" : null,
    "hits" : [ ]
  },
  "aggregations" : {
    "unique_values" : {
      "doc_count_error_upper_bound" : 0,
      "sum_other_doc_count" : 196,
      "buckets" : [
        {
          "key" : 21572669,
          "doc_count" : 7
        },
        {
          "key" : 170332394,
          "doc_count" : 4
        }
      ]
    }
  }
}

es内置语法如何聚合出buckets的总数量？？？该怎么写这个es查询语句？？？

Answer 1

用 "cardinality"

GET /mini_program_visit_log_230731/_search
{
    "size": 0,
    "query": {
        "bool": {
            "must": [
                { "match": { "page_path.keyword": "page/pages/webviewPage/webviewPage/bunny_jump" }},
                { "match": { "brand_id": 2617 }},
                {
                 "range": {
                   "create_time": {
                     "gte": 1690772400000,
                     "lte": 1690774200000
                   }
                 }
                }
            ]
        }
    },
    "aggs": {
      "unique_values": {
        "terms": {
          "field": "member_id"
        }
      },
      "unique_count": {
        "cardinality": {
          "field": "member_id"
        }
      }
    }
}