数组去重问题？

Question

实现数组去重并对重复的元素进行标记，如果重复 "isRepeat": true",否则为 "isRepeat": false"
但是函数实际输出的元素都标记为 "isRepeat": true"

 let arr=[ "11", "22","11","22","11","22","66"]
 norepeat(arr) {
            console.log('arr',arr)
            const uniqueArr = [...new Set(arr)]  
            const result = []  
            const tempArr = []    
            for (let i = 0; i < arr.length; i++) {  
                if (arr.find(item => item === uniqueArr[i] )) { 
                tempArr.push(uniqueArr[i])
                if(uniqueArr.some(item => item ===  tempArr[i])){
                    result.push({ value: uniqueArr[i], isPublic: true });
                }else {    
                   result.push({ value: uniqueArr[i], isPublic: false });  
                }  
             }    
            }  
                return result
            }
//期望
[
    {
        "value": "11",
        "isPublic": true
    },
    {
        "value": "22",
        "isPublic": true
    },
    {
        "value": "66",
        "isPublic": false
    }
]
//实际
[
    {
        "value": "11",
        "isPublic": true
    },
    {
        "value": "22",
        "isPublic": true
    },
    {
        "value": "66",
        "isPublic": true
    }
]

Answer 1

array.some方法只要数组内容有一个返回为true，它就会返回true，你这块的判断有问题。

如果是我的话，我会这样写：

const arr = [ "11", "22","11","22","11","22","66"]
function norepeat(arr) {
  const result = [];
 
  arr.forEach(i=>{
    const curResItem = result.find(r=>r.value===i);
    if (curResItem) {
      curResItem.isRepeat = true;
    } else {
      result.push({
        value: i,
        isRepeat: false,
      });
    }
  })
   
  return result;
}
   
const res = norepeat(arr);

Answer 2

用map可以区分字符数字和真实的number，如果不需要区分用{}就可以了
var translate = arr => [...arr.reduce((map, v) => map.set(v, map.has(v)),new Map).entries()].map(([v,b]) => ({value: v, isRepeat: b}))

Answer 3

使用了lastIndexOf，仅供参考。

let arr=[ "11", "22","11","22","11","22","66"]

function norepeat(arr) {
    const result = []
    const map = []
    for(let i = 0; i < arr.length; i++){
        if (map.includes(arr[i])) {
            continue;
        } else {
            map.push(arr[i])
        }
        let index = arr.lastIndexOf(arr[i])
        if (index === i){
            result.push({
                value: arr[i],
                isRepeat: false
            })
        } else {
            result.push({
                value: arr[i],
                isRepeat: true
            })
        }
        
    }
    return result;
}