如图所示,python脚本如何清空之前的输出到光标位置?

Question

不需要清理这个位置

第二个进度条出现的时候 清空如图所示区域

为什么无法清理为什么用交互式命令后inquirer向清理之前的，却无法清理

import importlib

import inquirer

from crontabs import Crontab

if __name__ == '__main__':
    # Tasks.four_screen()
    # result_dataframe = pd.read_excel(f'assets{os.sep}旗舰店链接汇总.xlsx').merge(
    #     pd.read_csv(os.path.join('cache', 'sales_data.csv')), on='店铺')
    # data = result_dataframe[result_dataframe['业绩归属'] != '其他'][
    #     ['业绩归属', '昨日销售量', '昨日销售额', '本月销售量', '本月销售额', '销量目标', '销售额目标']]
    # print(data)
    # result_dataframe.to_csv('aaa.csv')
    # exit(0)
    crawler_type = [
        inquirer.List(
            "crawler",
            message="请选择工具",
            choices=["semrush",
                     '网站截图工具',
                     '商品价格监控',
                     '领星业绩统计',
                     '亚马逊',
                     '定时任务',
                     '更新驱动',
                     # '版本更新'
                     ],
        ),
    ]
    try:
        crawler_name = inquirer.prompt(crawler_type)['crawler']
        if crawler_name == 'semrush':
            module = importlib.import_module("crawler.semrush.main")
            module.control_panel()
        elif crawler_name == '更新驱动':
            from foundation.selenium.update_chrome_driver import download
            download()
        elif crawler_name == '商品价格监控':
            from crawler.price_monitor import run
            run()
        elif crawler_name == '领星业绩统计':
            from office.lingxing import performance
        elif crawler_name == '定时任务':
            print("\r", end='', flush=True)
            Crontab().control_panel()
        elif crawler_name == '亚马逊':
            pass
    except TypeError:
        pass

import time

import inquirer
from apscheduler.schedulers.background import BackgroundScheduler

from crontabs.Tasks import Tasks
from concurrent.futures import ThreadPoolExecutor


def test():
    Tasks.four_screen()


executor = ThreadPoolExecutor(max_workers=5)  # 这里设置最大工作线程数为 5，可以根据需求进行调整

scheduler = BackgroundScheduler(executor=executor)

scheduler.add_job(Tasks.ling_xing_order_and_listing, 'cron', name="每小时运行领星订单和listing", hour='1-23',
                  minute='0', second='0')

scheduler.add_job(Tasks.four_screen, 'cron', name="领星截屏", day_of_week='1-5', hour='8,13,17', minute='0',
                  second='0')
scheduler.add_job(Tasks.dingding, 'cron', name="业绩推送", args=[], month='*', day='*', hour='5')
scheduler.add_job(test, 'interval', seconds=1,max_instances=1)


class Crontab:
    @staticmethod
    def control_panel():
        menu = inquirer.prompt([
            inquirer.List(
                'menu',
                message="执行什么操作?",
                choices=["开始运行", "查看列表"],
            ),
        ])['menu']
        if menu == "开始运行":
            try:
                scheduler.start()
                while True:
                    pass
            except (KeyboardInterrupt, SystemExit):
                # 在接收到 KeyboardInterrupt 或 SystemExit 信号时，关闭调度器
                scheduler.shutdown()
        if menu == "查看列表":
            scheduler.print_jobs()

Answer 1

\r 可以做到。运行下面代码看看是不是你要的效果:

import time

for i in range(10):
    print(f"{i=}", end="\r", flush=True)
    time.sleep(1)

或者通过ANSI控制字符来控制终端的字符行为:

import sys


def clear_console():
    # 这个会将整个缓存行全部清理，鼠标无法下滑显示上方的内容
    # sys.stdout.write("\033[2J\033[3J\033[H")    # 改动版本

    # 这个就单纯是清屏，但是不同终端表现有点不同，vscode下的终端可以达到清理的效果，
    # 鼠标滑动，没有历史遗留；但是mac终端或者其他终端显示，只是将上方内容向上做了隐藏
    # 鼠标滑动，还能看到原先的内容
    sys.stdout.write("\033[2J\033[H")

把这个函数插入到你想使用的地方就可以实现清屏。

• ESC - sequence starting with ESC (\x1B) or (\033)

ESC Code Sequence	Description
ESC[J	erase in display (same as ESC[0J)
ESC[0J	erase from cursor until end of screen
ESC[1J	erase from cursor to beginning of screen
ESC[2J	erase entire screen
ESC[3J	erase saved lines
ESC[K	erase in line (same as ESC[0K)
ESC[0K	erase from cursor to end of line
ESC[1K	erase start of line to the cursor
ESC[2K	erase the entire line

除此之外，你还可以实现针对行的清除，我曾经有实现过这个逻辑，代码粘贴给你:

import sys


def clear_lines_(num_lines: int):
    for _i in range(num_lines, -1, -1):
        # Move the cursor up 'num_lines' lines
        sys.stdout.write("\033[1A")
        # Clear the lines
        sys.stdout.write("\033[2K")
    # Move the cursor back to the beginning of the first cleared line
    sys.stdout.write("\033[{}G".format(0))

ANSI字符集的资料很多，这里我贴出来一个 ANSI Escape Sequences