harmonyo 如何通过 filterById 方法根据事件ID过滤日历事件？

Question

harmonyo 如何通过 filterById 方法根据事件ID过滤日历事件？

Answer 1

通过 filterById 方法根据事件ID过滤日历事件参考代码如下：

import { BusinessError } from '@kit.BasicServicesKit';
import { calendarMgr } from '../entryability/EntryAbility';

let calendar : calendarManager.Calendar | undefined = undefined;
let id1: number = 0;
let id2: number = 0;
const date = new Date();
const event1: calendarManager.Event = {
  type: calendarManager.EventType.NORMAL,
  startTime: date.getTime(),
  endTime: date.getTime() + 60 * 60 * 1000
};
const event2: calendarManager.Event = {
  type: calendarManager.EventType.IMPORTANT,
  startTime: date.getTime(),
  endTime: date.getTime() + 60 * 60 * 1000
};
calendarMgr?.getCalendar(async (err: BusinessError, data:calendarManager.Calendar) => {
  if (err) {
    console.error(`Failed to get calendar. Code: ${err.code}, message: ${err.message}`);
  } else {
    console.info(`Succeeded in getting calendar, data -> ${JSON.stringify(data)}`);
    calendar = data;
    await calendar.addEvent(event1).then((data: number) => {
      console.info(`Succeeded in adding event, id -> ${data}`);
      id1 = data;
    }).catch((err: BusinessError) => {
      console.error(`Failed to add event. Code: ${err.code}, message: ${err.message}`);
    });
    await calendar.addEvent(event2).then((data: number) => {
      console.info(`Succeeded in adding event, id -> ${data}`);
      id2 = data;
    }).catch((err: BusinessError) => {
      console.error(`Failed to add event. Code: ${err.code}, message: ${err.message}`);
    });
    const filter = calendarManager.EventFilter.filterById([id1, id2]);
    calendar.getEvents(filter).then((data: calendarManager.Event[]) => {
      console.info(`Succeeded in getting events filter by id, data -> ${JSON.stringify(data)}`);
    }).catch((err: BusinessError) => {
      console.error(`Failed to filter by id. Code: ${err.code}, message: ${err.message}`);
    });
  }
});