<ul>
<li class="_photo-item" data-type="a" data-path="0">1</li>
<li class="_photo-item" data-type="b" data-path="1">1</li>
<li class="_photo-item" data-type="c" data-path="2">1</li>
<li class="_photo-item" data-type="d" data-path="3">1</li>
<li class="_photo-item" data-type="e" data-path="4">1</li>
<li class="_photo-item" data-type="f" data-path="5">1</li>
<li class="_photo-item" data-type="g" data-path="6">1</li>
<li class="_photo-item" data-type="h" data-path="7">1</li>
<li class="_photo-item" data-type="i" data-path="8">1</li>
<li class="_photo-item" data-type="g" data-path="9">1</li>
</ul>
<script type="text/javascript">
$(function () {
var suns = $('._photo-item').length;
var employees =[
{"paths":" ","types":" "},
];
console.log(employees);
for (var i = 0; i < suns; i++) {
employees[i].paths = $('._photo-item').eq(i).data('path');
employees[i].types = $('._photo-item').eq(i).data('type');
console.log("是否循环:"+i);
};
console.log(employees);
})
</script>
为什么,i只循环了一次,只写入了第一次的数据。
而且报错,paths为空
因为你的employees[1] 是undefined,报错了,导致停止运行。所以才只循环1次就终止了。