coffee-script 编译后，怎么才能避免出现不需要出现的return呢？

Question

coffeescript 新手，请多多指教。

coffee上的代码是：

refine = (wheat,chaff...) -> 
    console.log "The best: #{wheat}"
    console.log "The rest: #{chaff.join(',')}"

refine 'one','two','three','four'

编译出来后：

(function() {
  var refine,
    __slice = [].slice;

  refine = function() {
    var chaff, wheat;
    wheat = arguments[0], chaff = 2 <= arguments.length ? __slice.call(arguments, 1) : [];
    console.log("The best: " + wheat);
    return console.log("The rest: " + (chaff.join(',')));
  };

  refine('one', 'two', 'three', 'four');

}).call(this);

refine函数里面最后一行，多了return，实际中应该不需要这个return的，为什么会被这样编译出来呢？
需要去掉吗？怎么去掉？
不需要去掉吗？为什么？

Answer 1

最后一行写一个return或者undefined

refine = (wheat,chaff...) -> 
    console.log "The best: #{wheat}"
    console.log "The rest: #{chaff.join(',')}"
    return

refine 'one','two','three','four'

or

refine = (wheat,chaff...) -> 
    console.log "The best: #{wheat}"
    console.log "The rest: #{chaff.join(',')}"
    undefined

refine 'one','two','three','four'

http://stackoverflow.com/questions/7391493/is-there-any-way-to-not-ret...