如何给go不定参数的函数传递一个数组参数？

Question

正确

err = c.Insert(moejson.Mjson{"name": "m1"}, moejson.Mjson{"name": "m2"})

失败了

inserter:=[2]Bson.M{moejson.Mjson{"name": "m1"}, moejson.Mjson{"name": "m2"}}
err = c.Insert(inserter)

Answer 1

使用golang的slice打散语法糖,将数组对应到可变参数列表上, 参加下面的main函数中slice的传递方式;

λ  ~/workingspace/  cat x.go 
package main

import "fmt"

func show(args ...int){
    for _, v := range args {
        fmt.Println(v)
    }
}

func main() {
    slice:=[]int{1,2,3,4}
    show(slice...)
}
λ  ~/workingspace/  go run x.go 
1
2
3
4
λ  ~/workingspace/

Answer 2

Inserter ...