django 表单分页

Question

                    {% ifnotequal cur_page 1 %}
                        <li><a href="/product/pdt">|&lt;</a></li>
                        <li>
                            <a href="/product/pdt?page_id={{ cur_page|add:-1 }}&{{ url }}"><span>&lt;</span></a>
                        </li>
                    {% else %}
                        <li><span style="color: #d1d1d1;">|&lt;</span></li>
                        <li><span style="color: #d1d1d1;">&lt;</span></li>
                    {% endifnotequal %}

                    <li>
                        <a href="/product/pdt?page_id={{ cur_page }}&{{ url }}">{{ cur_page }}</a>
                    </li>

                    {% ifnotequal cur_page total_page %}
                        <li>
                            <a href="/product/pdt?page_id={{ cur_page|add:1 }}&{{ url }}">{{ cur_page|add:1 }}</a>
                        </li>

                        <li>
                            <a href="/product/pdt?page_id={{ cur_page|add:2 }}&{{ url }}">{{ cur_page|add:2 }}</a>
                        </li>

                    {% endifnotequal %}

                    {% if next %}
                        <li>
                            <a href="/product/pdt?page_id={{ cur_page|add:3 }}&{{ url }}"><span>&gt;</span></a>
                        </li>
                    {% else %}
                        <li><span style="color: #d1d1d1;">&gt;</span></li>
                    {% endif %}

                    {% ifnotequal cur_page total_page %}
                        <li>
                            <a href="/product/pdt?page_id={{ total_page }}&{{ url }}"><span>&gt;|</span></a>
                        </li>
                    {% else %}
                        <li><span style="color: #d1d1d1">&gt;|</span></li>
                    {% endifnotequal %}

点击到最后一页，效果如下：

但实际上只有9页，判断next（即当前页是否存在下一页）标签时 加 3 溢出 到10页。
1、要求显示的页码范围数为3,不足的为2或者1；
请教该如何处理？

Answer 1

在Paginator上再封装一层Spagination ,Views调用

obj = Model.object.filter(条件)
pagin = Spagination.wraper(obj, pageSize, page)
return pagin

Spagination类代码

#coding=utf-8

from django.core.paginator import Paginator

class Spagination(object):
    def __init__(self, total, page=1, perpage=10):
        self.total = total
        self.pages = self.total / perpage + 1 if (self.total % perpage) > 0 else self.total / perpage

        self.page = page
        self.perpage = perpage

        self.prev_num = page-1 if page > 1 else None
        self.next_num = page+1 if page*perpage < total else None

        self.has_prev = True if self.prev_num else False
        self.has_next = True if self.next_num else False

        self.visible_pages = self.iter_pages()

    def prev(self):
        if self.prev_num:
            return Spagination(self.total, page=self.page-1, perpage=self.perpage)
        raise 'There is no prev page!'

    def next(self):
        if self.next_num:
            return Spagination(self.total, page=self.page+1, perpage=self.perpage)
        raise 'There is no next page!'

    def iter_pages(self, left_edge=5, right_edge=4, all=9):
        left_list, right_list = [], []

        for p in range(1,left_edge):
            if self.page - p > 0:
                left_list.insert(0, self.page - p)

        for p in range(1,right_edge):
            if self.page + p <= self.pages:
                right_list.append(self.page + p)

        if len(left_list) < left_edge and right_list:
            for i in range(all-len(left_list)-len(right_list)-1):
                if right_list[-1]+1 <= self.pages:
                    right_list.append(right_list[-1]+1)

        if len(right_list) < right_edge and left_list:
            for i in range(all-len(left_list)-len(right_list)-1):
                if left_list[0]-1 > 0:
                    left_list.insert(0, left_list[0]-1)

        return left_list+[self.page]+right_list

    def setItems(self, items):
        self.items = items

    @classmethod
    def wraper(cls, objs, limit, current_page):
        paginator = Paginator(objs, limit)
        items = paginator.page(current_page)

        pagin = Spagination(paginator.count, current_page, limit)
        pagin.setItems(items)
        return pagin

template代码

<div class="pagerbox">
    {%if pagin.has_prev %}
        <a href="javascript:void(0)" page="{{pagin.prev_num}}" >上页</a>
    {%endif%}
    <a href="javascript:void(0)" page="1" {%if pagin.page == 1%}class="current_page"{%endif%}>首页</a>
    {%for p in pagin.visible_pages%}
        {%if p != 1 and p != pagin.pages%}
            <a href="javascript:void(0)" page="{{ p }}" {%if pagin.page == p %}class="current_page"{%endif%}>{{p}}</a>
        {%endif%}
    {%endfor%}
    <a href="javascript:void(0)" page="{{ pagin.pages }}" {%if pagin.page == pagin.pages%}class="current_page"{%endif%}>尾页</a>
    {%if pagin.has_next %}
        <a href="javascript:void(0)" page="{{pagin.next_num}}">下页</a>
    {%endif%}
</div>

Answer 2

可以再加一层判断，判断是否超出