这种类型的json怎么解析

Question

reqparam={
    "pub": {
        "platno": "jcrzzl",
        "cmpseq": "20171128000358000001",
        "zoneno": "1302",
        "phybrno": "12032150",
        "orderno": "-9223372036854775808",
        "assurerno": "528",
        "cmpdate": "20171128",
        "cmptime": "000358"
    },
    "req": {
        "custname": "小明",
        "idno": "330681199003000004",
        "relation": "本人",
        "result": "099",
        "loanCrdt": "-",
        "cardCrdt": "-",
        "leftNum": "-",
        "leftAmount": "-",
        "note": "图片下载失败，请检查后再提交!"
    }
}

前面带个reqparam=

Answer 1

直接用eval

Answer 2

目前它还不是json啊 去掉"reqparam="才是json格式的

Answer 3

直接用json_decode($reqparam,true);转化成数组不可以吗?

Answer 4

说明它不合格。
只能把 reqparam= 去掉啦，看着就是固定格式，位于开头，直接去掉再读，完美。

Answer 5

以 = 进行分割 取后面的串进行解析。

Answer 6

<?php

$str = <<<EOF
reqparam={
    "pub": {
        "platno": "jcrzzl",
        "cmpseq": "20171128000358000001",
        "zoneno": "1302",
        "phybrno": "12032150",
        "orderno": "-9223372036854775808",
        "assurerno": "528",
        "cmpdate": "20171128",
        "cmptime": "000358"
    },
    "req": {
        "custname": "小明",
        "idno": "330681199003000004",
        "relation": "本人",
        "result": "099",
        "loanCrdt": "-",
        "cardCrdt": "-",
        "leftNum": "-",
        "leftAmount": "-",
        "note": "图片下载失败，请检查后再提交!"
    }
}
EOF;

$replaced_str = str_replace('reqparam=', '', $str);
$json = json_decode($replaced_str, true);
print_r($json);

Answer 7

必须要把reqparam= 清楚才能解析的

Answer 8

我个人用法是，先用 strpos(); 函数获取到第一个 '{',通过 substr(); 函数去除前面部分。再进行解析。由于前阵子获取出现过这种情况，还有就是出现损坏的 json 字符串返回，然后在裁剪前面字符后为预防万一还做了个检测是否 json 是否能被 json_descde(); 函数转换，如果不行就进行递归修理。

Answer 9

let reqparam = {
  "pub": {
      "platno": "jcrzzl",
      "cmpseq": "20171128000358000001",
      "zoneno": "1302",
      "phybrno": "12032150",
      "orderno": "-9223372036854775808",
      "assurerno": "528",
      "cmpdate": "20171128",
      "cmptime": "000358"
  },
  "req": {
        "custname": "小明",
        "idno": "330681199003000004",
        "relation": "本人",
        "result": "099",
        "loanCrdt": "-",
        "cardCrdt": "-",
        "leftNum": "-",
        "leftAmount": "-",
        "note": "图片下载失败，请检查后再提交!"
    }
};
console.log(reqparam.pub.assurerno); //直接取值,结果528
let arr = Object.keys(reqparam).map(function(re){
  return reqparam[re];
});
console.log(arr);

Answer 10

我觉得先str_replace去掉前面的参数和等号，然后json_decode应该是简洁的吧

Answer 11

格式错误，无法识别。校验网址：https://www.bejson.com/