js正则表达式分析求教，急，各位好汉帮忙

Question

#qq_23_jpg#,这样一个类型的编码，我想用js正则表达式取出其中的qq，23和jpg，写成的结果这样表示<img src="src=image/qq/23.jpg"/>
该怎么写转换式呢？求教！！！

Answer 1

"#qq_23_jpg#".replace(/#(.*?)_(.*?)_(.*?)#/,'<img src="image/$1/$2.$3"/>')

Answer 2

  var reg = /[\dA-Za-z]+/g;
  var arr = [];
  str.replace(reg,function( v ){
    arr.push( v );
  });
  // 数组里面依次存着qq 23 jpg
  console.log(arr);

Answer 3

let str = "#qq_23_jpg#";
let reg = /#(.*?)_(.*?)_(.*?)#/;
let url = str.replace(reg,'image/$1/$2.$3');
img.setAttribute('src', url);

Answer 4

function resolvePicParamToURL(param) {
  var match = param.match(/#([^_]+)_([^_]+)_(\w+)#/) || [];

  return ['image', match[1], match[2]].join('/') + '.' + match[3];
}

resolvePicParamToURL('#qq_23_jpg#')

Answer 5

var str = '#qq_23_jpg#';
var reg = /^#(\w{2})_(\d{2})_(\w{3})#$/;
str.replace(reg, function($0, $1, $2, $3){
    return $1+'/'+$2+'/'+$3;
});

Answer 6

replace('-','/')