动态获取数据？路径拼接？

Question

console.log(pic)//商品圖片地址
这个是打印出来的图片地址http://www.zhani.com//Uploads...
$('.tu img').attr('src','+pic+');
怎么吧pic拼接进去呢，求大神帮忙，试了好多种方法都不对

Answer 1

$('.tu img').attr('src',pic);

Answer 2

$('.tu img').attr('src',pic);

Answer 3

$('img').src = 'https://tpc.googlesyndication...'