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这种方法为什么无法修改transform的translate？

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拉斯戈柏尔的兔子
    1310

    <!DOCTYPE html>
    <html lang="en">
    <head>
    <meta charset="UTF-8">
    <meta name="viewport" content="width=device-width, initial-scale=1.0">
    <title>Document</title>
    <style>

    #aaa{
  width: 100px;height: 100px;
  background-color: orange;
  transform: translateX(150px);
}

    </style>
    </head>
    <body>

    <div id="aaa">
    </div>

    <script>

    let a = document.querySelector('#aaa')
let aStyle = window.getComputedStyle(a)
console.log(aStyle.transform);
function set() {
  setTimeout(() => {
    aStyle.style.transform= "translateX(50px)";
}, 1000);
}
set()

    </script>
    </body>
    </html>

    javascriptcss3csshtmlhtml5
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    2 个回答
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    chatgpt
      4.2k11043
      ✓ 已被采纳

      不该是 aStyle.style.transform = 'translateX(50px)'，
      应该是 a.style.transform = 'translateX(50px)' 吧
      然后考虑兼容性，把 webkitTransform 也写上

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      kikong
        19.1k31320
        The returned object is the same CSSStyleDeclaration type as the object returned from the element's style property. However, the two objects have different purposes:
        • The object from getComputedStyle is read-only, and should be used to inspect the element's style — including those set by a <style> element or an external stylesheet.
        • The _element_.style object should be used to set styles on that element, or inspect styles directly added to it from JavaScript manipulation or the global style attribute.
        1. getComputedStyle返回的是只读的
        2. 需要element.style方式更新
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