判断每一个层级的children,如果children为空那么就把那条children对应的数组给删除,数据结构不变,仅删除
数据结构↓
const data = [{
name: '水果大全',
id: '111',
children: [{
name: '浆果类',
id: '112',
children: [{
name: '草莓',
id: '113'
}, {
name: '桑椹',
id: '114'
}]
}, {
name: '柑橘类',
id: '116',
children: []
}]
}, {
name: '奥特曼大全',
id: '119',
children: [{
name: '昭和类',
id: '120',
children: [{
name: '杰克',
id: '121'
}, {
name: '泰罗',
id: '122'
}]
}, {
name: '平成类',
id: '124',
children: []
}]
}, {
name: '电影大全',
id: '125',
children: []
}, {
name: '手机大全',
id: '127',
children: []
}]
理想效果↓
const data = [{
name: '水果大全',
id: '111',
children: [{
name: '浆果类',
id: '112',
children: [{
name: '草莓',
id: '113'
}, {
name: '桑椹',
id: '114'
}]
}]
}, {
name: '奥特曼大全',
id: '119',
children: [{
name: '昭和类',
id: '120',
children: [{
name: '杰克',
id: '121'
}, {
name: '泰罗',
id: '122'
}]
}]
}]
我该怎么操作才能达到效果呢~..
比如说像
{
name: '电影大全',
id: '125',
children: []
}
这条数据,他的children为空,所以把这条数组删除
感谢各位大神大哥的指导,先感谢你们的回答,小弟感激不尽,还请轻喷!
你之前不是问过类似问题么js/vue/react 如何优化以下代码,参考那个问题的回答稍稍修改下: