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当我将代码更改为 php（来自 html）时，我不知道为什么会收到此错误。当文件的扩展名是 html 时，代码工作正常。
<?php?>
<html lang="en">
<head>
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.5/css/bootstrap.min.css">
<!-- Latest compiled and minified CSS -->
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.5/css/bootstrap.min.css">
<link rel="stylesheet" href="css/manual.css">
<!-- Optional theme -->
<!-- Latest compiled and minified JavaScript -->
<script src="http://code.jquery.com/jquery-latest.min.js"
type="text/javascript"></script>
<!-- Latest compiled and minified JavaScript -->
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.5/js/bootstrap.min.js"></script>
<script src="http://ajax.aspnetcdn.com/ajax/jquery.validate/1.14.0/jquery.validate.js"></script>
<script src="http://ajax.aspnetcdn.com/ajax/jquery.validate/1.14.0/jquery.validate.min.js"></script>
<title>Register</title>
</head>
<body>
<nav class="navbar navbar-default" id="navBar">
</nav>
<div class="full">
<div class="col-xs-12">
<!--Side Bar-->
<div class="col-xs-3" id="navSide">
</div>
<div class="col-xs-6" id="signUpForm">
<h1>Register Page</h1>
<form role="form" id="signUpForm">
<div class="form-group">
<div class="form-inline spacer-12">
<input type="text" class="form-control" name="userFirstname" placeholder="First Name">
<input type="text" class="form-control" name="userLastName" placeholder="Last Name">
</div>
</div>
<div class="form-group ">
<input type="text" class="form-control"
name="userEmail"
placeholder="Email">
</div>
<div class="form-group ">
<input type="password" class="form-control" name="userPassword" placeholder="Password">
</div>
<div class="form-group ">
<input type="password" class="form-control" name="confirmPassword" placeholder="Password">
</div>
<div class="form-group ">
<label> Birthday* </label>
<input type="date" class="form-control" name="userBirthday" placeholder="Birthday">
</div>
<input type="submit" class="btn btn-info spacer-12" style="clear:both" >
</form>
</div>
</div>
</div>
<script src="js/startup.js"></script>
<script src="js/signup.js"></script>
</body>
</html>
<?php?>
那么这是我的jQuery验证代码
$(document).ready(function(){
$('#signUpForm').validate({
errorElement: "span",
errorClass: "help-block",
rules:{
userFirstName:{
required: true
},
userLastName:{
required: true
},
userEmail:{
required: true
},
userPassword:{
required: true
},
confirmPassword:{
required: true
},
userBirthday:{
required: true
}
},
submitHandler: function (form) { // for demo
alert('valid form submitted'); // for demo
return false; // for demo
},
highlight: function(element) {
$(element).closest('.form-group').addClass('has-error').addClass('red-border');
},
unhighlight: function(element) {
$(element).closest('.form-group').removeClass('has-error').addClass('has-success').removeClass('red-border');
}
});
});
当我单击提交按钮时，此代码会导致错误（JQuery Validate Uncaught TypeError: Cannot read property ‘settings’ of undefined ）但该错误是暂时的，并且会在一段时间内消失。
原文由 Robert Limanto 发布，翻译遵循 CC BY-SA 4.0 许可协议
您定义了两个具有相同名称的 id，而 id 应该是唯一的。
尝试从
<div class="col-xs-6" id="signUpForm">中删除id