遍历嵌套的 JSON 对象并使用 Python 获取值

Question

我正在使用 Python；我需要遍历 JSON 对象并检索嵌套值。我的数据片段如下：

  "bills": [
{
  "url": "http:\/\/maplight.org\/us-congress\/bill\/110-hr-195\/233677",
  "jurisdiction": "us",
  "session": "110",
  "prefix": "H",
  "number": "195",
  "measure": "H.R. 195 (110\u003csup\u003eth\u003c\/sup\u003e)",
  "topic": "Seniors' Health Care Freedom Act of 2007",
  "last_update": "2011-08-29T20:47:44Z",
  "organizations": [
    {
      "organization_id": "22973",
      "name": "National Health Federation",
      "disposition": "support",
      "citation": "The National Health Federation (n.d.). \u003ca href=\"http:\/\/www.thenhf.com\/government_affairs_federal.html\"\u003e\u003ccite\u003e Federal Legislation on Consumer Health\u003c\/cite\u003e\u003c\/a\u003e. Retrieved August 6, 2008, from The National Health Federation.",
      "catcode": "J3000"
    },
    {
      "organization_id": "27059",
      "name": "A Christian Perspective on Health Issues",
      "disposition": "support",
      "citation": "A Christian Perspective on Health Issues (n.d.). \u003ca href=\"http:\/\/www.acpohi.ws\/page1.html\"\u003e\u003ccite\u003ePart E - Conclusion\u003c\/cite\u003e\u003c\/a\u003e. Retrieved August 6, 2008, from .",
      "catcode": "X7000"
    },
    {
      "organization_id": "27351",
      "name": "Natural Health Roundtable",
      "disposition": "support",
      "citation": "Natural Health Roundtable (n.d.). \u003ca href=\"http:\/\/naturalhealthroundtable.com\/reform_agenda\"\u003e\u003ccite\u003eNatural Health Roundtable SUPPORTS the following bills\u003c\/cite\u003e\u003c\/a\u003e. Retrieved August 6, 2008, from Natural Health Roundtable.",
      "catcode": "J3000"
    }
  ]
},

我需要遍历“bills”中的每个对象并获取“session”、“prefix”等，我还需要遍历每个“organizations”并获取“name”、“disposition”等。我有以下代码:

 import csv
import json

path = 'E:/Thesis/thesis_get_data'

with open (path + "/" + 'maplightdata110congress.json',"r") as f:
data = json.load(f)
a = data['bills']
b = data['bills'][0]["prefix"]
c = data['bills'][0]["number"]

h = data['bills'][0]['organizations'][0]
e = data['bills'][0]['organizations'][0]['name']
f = data['bills'][0]['organizations'][0]['catcode']
g = data['bills'][0]['organizations'][0]['catcode']

for i in a:
    for index in e:
          print ('name')

它多次返回字符串“name”。

建议？

原文由 Collective Action 发布，翻译遵循 CC BY-SA 4.0 许可协议

Answer 1

这可能对你有帮助。

 def func1(data):
    for key,value in data.items():
        print (str(key)+'->'+str(value))
        if type(value) == type(dict()):
            func1(value)
        elif type(value) == type(list()):
            for val in value:
                if type(val) == type(str()):
                    pass
                elif type(val) == type(list()):
                    pass
                else:
                    func1(val)
func1(data)

您所要做的就是将 JSON 对象作为字典传递给函数。

还有这个 python 库可以帮助你解决这个问题。你可以在这里找到这个 -> JsonJ

和平兄弟！

原文由 Joish 发布，翻译遵循 CC BY-SA 4.0 许可协议