如何在spring rest api中将字符串转换为json格式

Question

这是代码：

 @RequestMapping(value="/find/city={city}", method=RequestMethod.GET)
public @ResponseBody String getCity(@PathVariable String city) throws JsonParseException, IOException
{
  ObjectMapper mapper = new ObjectMapper();
  SimpleBeanPropertyFilter theFilter = SimpleBeanPropertyFilter.serializeAllExcept("id","miscellaneous","country","foundin","code","latlong","state");
  FilterProvider filters = new SimpleFilterProvider().addFilter("myFilter", theFilter);
  String content = "";
  StringBuilder builder = new StringBuilder();
  List<Master_City> list = City_Repository.findByCityLikeIgnoreCase(city);
 for (Master_City json : list)
  {
     builder.append( mapper.writer(filters).writeValueAsString(json));
    }
 content = builder.toString();
 return content;
}

输出不在 json 中，它是一个字符串：

 {"indexid":65,"city":"Barcelona"}{"indexid":158,"city":"Dillons Bay"}     {"indexid":232,"city":"East London"}{"indexid":411,"city":"Londonderry"{"indexid":587,"city":"Thessaloniki"}{"indexid":818,"city":"Bouillon"}{"indexid":1719,"city":"Flin Flon"}{"indexid":2073,"city":"Clonmel"}

我需要这种格式：

[ { “indexid”: “425”, “city”: “Flin Flon” }, { “indexid”: “220”, “city”: “伦敦” }, { “indexid”: “525”, “city” : “朗年” } ]

原文由 Naresh Gounder 发布，翻译遵循 CC BY-SA 4.0 许可协议

Answer 1

您可以使用 Spring Boot JSONObject

例子 ：

 String content = "{"id":1,"name":"ram"}";
JSONObject jsonObject= new JSONObject(content );

之后，您可以从 spring 控制器返回 jsonObject。

从 这里 依赖检查最新版本：

 <dependency>
 <groupId>org.springframework.boot</groupId>
 <artifactId>spring-boot-configuration-processor</artifactId>
 <version>2.0.1.RELEASE</version>
</dependency>

原文由 Bheem Singh 发布，翻译遵循 CC BY-SA 4.0 许可协议